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How to calculate cooling time in injection molding?
Cooling Time in Injection Molding
Cooling time is typically 50–70% of the total cycle time and is calculated using the following formula:
Core Formula (Jansson's Equation)
Where:
Symbol | Meaning | Typical Units |
tc | Cooling time | seconds |
s | Wall thickness (heaviest section) | mm or m |
α | Thermal diffusivity of the plastic | m²/s |
Tm | Melt temperature | °C |
Tw | Mold wall temperature | °C |
Te | Ejection temperature | °C |
Thermal Diffusivity
α=ρ⋅cpk
k = thermal conductivity (W/m·K)
ρ = density (kg/m³)
c_p = specific heat capacity (J/kg·K)
Typical values for common materials:
Material | α (×10⁻⁷ m²/s) | T_m (°C) | T_e (°C) |
PP | 0.77 | 230 | 90 |
ABS | 1.0 | 240 | 85 |
Nylon (PA6) | 1.1 | 260 | 100 |
HDPE | 1.2 | 220 | 70 |
POM (Acetal) | 0.9 | 210 | 100 |
Step-by-Step Example
Given: PP part, wall thickness = 3 mm, T_m = 230°C, T_w = 30°C, T_e = 90°C, α = 0.77 × 10⁻⁷ m²/s
Convert thickness: s = 0.003 m
Calculate the log term: ln(4/π × (230−30)/(90−30)) = ln(1.273 × 3.33) = ln(4.24) ≈ 1.44
Apply formula: t_c = (0.003²) / (π² × 0.77×10⁻⁷) × 1.44 ≈ 17 seconds
Key Rules of Thumb
Thicker walls = longer cooling — time scales with the square of wall thickness (doubling thickness → 4× cooling time)
Lower mold temp → faster cooling but risk of sink marks/warpage
Target ejection temp is typically 20–30°C below the material's heat deflection temperature (HDT)
Conformal cooling channels can reduce cooling time by 20–40%
Practical Tips
Use uniform wall thickness to avoid differential cooling and warpage
Cooling time is dominated by the thickest section, not the average
Simulation tools (Moldflow, Moldex3D) give more accurate results for complex geometries